Question

Gloria set aside $100 to buy school lunches for the year. Each school lunch cost $2. The inequality 100 – 2x < 20 can be used to find the number of school lunches Gloria can buy before she has less than $20 left. What is the solution to this inequality?

Answer 1

100 – 2x < 20

−2x + 100 < 20

−2x + 100 − 100 < 20 − 100

−2x < −80

−2x/2 < −80/2

x > 40