Question

What is the final temperature of 100g of water at -15°C added to a styrofoam cup filled with 220 g of water at 32°C?

Answer 1

Step-by-step explanation:

First off, let's call the -15 degree water solution1, and the 32 degree water solution2. The formula for this is

`t_f=((m_1*spheat_1*temp_1)+(m_*spheat_2*temp_2))/((m_1*spheat_1)+(m_2*spheat_2))`

where spheat is specific heat of water that I found to be 4182 J/(kgC). This means that we need our masses in kg and they are currently in g.

100 g = .100 kg and

220 g = .220 kg. Now we're ready to plug everything in:

`t_f=((.100*4182*-15)+(.220*4182*32))/((.100*4182)+(.220*4182))` and

`t_f=(-6273+29441.28)/(418.2+920.04)` and

`t_f=(23168.28)/(1338.24)` so

`t_f=17.3` °C