Answer:
see explanation
Explanation:
note that (sinx)² = sin²x
4sin²x - 2 = 0 ( add 2 to both sides )
4sin²x = 2 ( divide both sides by 4 )
sin²x =
=
( take square root of both sides )
sinx = ±
= ±
sinx =
( sinx > 0 , then x is in 1st/2nd quadrants )
x =
, π -
=
sinx = -
( sinx < 0 , then x is in 3rd/4th quadrants )
x = π +
=
, 2π -
=
solutions are
,
,
,
in the interval [ 0, 2π )