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What is the magnitude of the electric field strength at a point where an electron

experiences an electrostatic force of 8.3 x 10^-20 N?

1 Answer

3 votes

Answer:

Step-by-step explanation:

Use the equation


E=(q)/(F) where the charge, q, on the electron is 1.602 ×
10^{-19 :


E=(1.602*10^(-19))/(8.3*10^(-20)) so

E = 1.9 C/N

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