Question

Sum of three consecutive odd number is 69 find the prime number out​

Answer 1

`let \: the \: first \: number \: be \: x \\ x + (x + 2) + (x + 4) = 69 \\ 3x + 6 = 69 \\ 3x = 63\\ x = 21 \\ first = 21 \\ second = 21 + 2 =23 \\ third = 21+ 4 = 25\\ prime \: number \: is \: 23 \\ { \boxed{prime = 23}}`

Answer 2

23 is the prime number

Explanation:

let n, n + 2, n + 4 be the consecutive odd numbers, then

n + n + 2 + n + 4 = 69 ← simplify left side

3n + 6 = 69 ( subtract 6 from both sides )

3n = 63 ( divide both sides by 3 )

n = 21 , then

n + 2 = 21 + 2 = 23 and n + 4 = 21 + 4 = 25

The 3 numbers are 21, 23, 25 with prime number 23