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In a triangle HIJ, i = 6.6 inches, j = 6.4 inches and Angle,H=62º. Find the length of h, to the

nearest 10th of an inch.

In a triangle HIJ, i = 6.6 inches, j = 6.4 inches and Angle,H=62º. Find the length-example-1
User Barbra
by
5.7k points

2 Answers

0 votes

Answer:

6.7

Explanation:

square root and round

User Solomon Slow
by
5.4k points
5 votes

Answer:

7.6 inches

Explanation:

We solve the above question using the Law of Cosines.

The formula is given as:

h² = i² + j² - 2ij Cos H

h = √i² + j² - 2ij Cos H

From the above question:

i = 6.6 inches

j = 6.4 inches

Length h = ?

Angle H=62º.

Hence:

h= √6.6² + 6.4² - 2 × 6.6 × 64 × Cos 62

h = √43.56 + 40.96 - 84.48 × Cos 62

h = 7.64292 inches

Approximately to the nearest tenth, Length h = 7.6 inches

User Vicent
by
5.0k points