Question

37) The endpoint of the diameter in circle 0 are (-2,5) and (6,5), find the equation of the circle in standard form

Answer 1

3737373eieeeuehe3827373

Answer 2

(x-2)^2+y^2=16

Explanation:

If the center of the circle is (h,k) and the radius is r, then the equation of a circle is (x-h)^2+(y-k)^2=r^2 (with the Pythagorean theorem)

So, the center of this circle 0 is (2,0) and the radius is 4. Thus, the equation is (x-2)^2+y^2=16