Question

In ΔIJK, the measure of ∠K=90°, KJ = 65, IK = 72, and JI = 97. What is the value of the cosine of ∠J to the nearest hundredth?

Answer 1

`\cos(J) = 0.67`

Explanation:

Given

`\angle K = 90^o`

`KJ = 65`

`IK = 72`

`JI = 97`

Required

`\cos(J)`

The question is illustrated with the attached image.

From the image, we have:

`\cos(J) = (KJ)/(JI)`

This gives:

`\cos(J) = (65)/(97)`

`\cos(J) = 0.67010309278`

`\cos(J) = 0.67` --- approximated