Answer:
Explanation:
1). Since, XM is the radius of the circle,
Therefore, area of the circle =

=

=

= 452.39 units²
2). Circumference of a circle = 2πr
= 2π(XM)
= 2π(12)
= 24π
= 75.40 units
3). By applying Pythagoras theorem in ΔYXM,
YM² = XY² + XM²
(43)²= (XY)² + (12)²
1849 - 144 = (XY)²
XY = 41.29 units
4). tan(∠M) =
=

m∠M =

= 73.79°
5). Area of ΔXYM =

=

= 247.74 square units
6). Area of the minor sector created by ΔXYM =

=

= 92.73 units²