Question

How much energy is used when 14.3 moles of hydrosulfuric acid reacts with 17.1 moles

of oxygen?
2 H2S + 3 02 + 175 KJ
—->2 SO2 + 2 H20
Which substance is the limiting reactant?

Answer 1

O2 is the limiting reactant.

Step-by-step explanation:

Hello there!

In this case, according to the given information about this reaction, one could identify the limiting reactant by performing a mole ratio of H2S to SO2 and O2 to SO2:

`14.3molH_2S*(2molSO_2)/(2molH_2S)=14.3molSO_2 \\\\17.1molO_2*(2molSO_2)/(3molO_2)=11.4molSO_2`

Thus, since 17.1 moles of O2 yields fewer moles than 14.3 moles of H2S, we infer the former is the limiting reactant.

Regards!