Answer:
d. pOH = 12 => pH = 14 - 10 = 2 => most acidic
Step-by-step explanation:
pH = -log[H⁺] => [H⁺] = 10^-pH
By definition, if ...
[H⁺] > 10⁻⁷ > [OH⁻] => pH < -log(10⁻⁷) < 7 => pOH > 14 - 7 > 7 => acidic solution
[H⁺] = 10⁻⁷ = [OH⁻] => pH = -log(10⁻⁷) = 7 => pOH = 14 - 7 = 7 => neutral solution
[H⁺] < 10⁻⁷ < [OH⁻] => pH > -log(10⁻⁷) > 7 => pOH < 14 - 7 < 7 => basic solution
∴ From most basic to most acidic ...
a. pH = 12 => most basic
b. pOH = 5 => pH = 14 - 5 = 9
c. [H⁺] = 1 x 10⁻⁸ => pH = -log(10⁻⁸) = -(-8) = 8
d. pOH = 12 => pH = 14 - 10 = 2 => most acidic