Question

I have to get this so I pass help plz

Answer 1

`\boxed{\sf x=-2}`

`\boxed{\sf y=-4}`

Explanation:

First, Let's solve for x in -2x+2y=-4:

`\sf -2x+2y=-4`

Subtract 2y from both sides:

`\sf -2x+2y-2y=-4-2y`

`\sf -2x=-4-2y`

Divide both sides by -2:

`\sf \cfrac{-2x}{-2}=-\cfrac{4}{-2}-\cfrac{2y}{-2}`

`\bold{ x=y+2}`

Now, we'll substitute x=y+2 to 3x+3y=-18:

`\sf 3x+3y=-18`

→ let x=2+y

`\sf 3\bold{(2+y)}+3y=-18`

Simplify:

`\sf 6+6y=-18`

Now, let's solve for y in 6+6y=-18

`\sf 6+6y=-18`

Subtract 6 from both sides:

`\sf 6+6y-6=-18-6`

`\sf 6y=-24`

Divide both sides by 6:

`\sf \cfrac{6y}{6}=\cfrac{-24}{6}`

`\bold{ y=-4}`

Now, substitute y=-4 into x=2+y:

`\sf x=2+y`

→ let y = -4

`\sf x=2+\bold{-4}`

`\bold{x=-2}`

Therefore, x=-2 and y=-4.

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