Question

In an electrical circuit 200mC of charge flows through a 50kohm resistor in 90 seconds. What is the power

Answer 1

Answer:
`0.2464\ W`

Step-by-step explanation:

Given

Charge
`Q=200\ mC`

Resistance
`R=50\ k\Omega`

Time
`t=90\ s`

Charge is the amount of current flown in a particular time

`Q=It\\\Rightarrow 200* 10^(-3)=I* 90\\\\\Rightarrow I=(200* 10^(-3))/(90)\\\\\Rightarrow I=2.22* 10^(-3)\ A`

Power is the given by
`P=I^2R`

Insert values

`\Rightarrow P=\left(2.22* 10^(-3)\right)^2* 50* 10^3\\\\\Rightarrow P=246.42* 10^(-3)\ W\\\\\Rightarrow P=0.2464\ W`

The power is in the circuit is
`0.2464\ W`.