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If sec theta = 5/3 and the terminal point determined by theta is in quadrant 4, then:​

If sec theta = 5/3 and the terminal point determined by theta is in quadrant 4, then-example-1
User Uxonith
by
7.9k points

2 Answers

3 votes

Answer:

A. csc 0 = -5/4 or B. cos 0 = 3/5

User Mannopson
by
8.2k points
4 votes

Answer:

B or A

Explanation:

sec(theta) = 1/cos(theta)

cos(theta) = adjacent side / hypotenuse.

The csc(theta), the sin(theta) and the tan(theta) in quad 4 are all minus

Since the cos(theta) is positive in quad 4, B is going to be the answer.

The value for sin(theta) should be sin(theta) = - 4/5 not 2/5

Tan(theta) = - 4/3

Note: 4 is found by using the Pythagorean Theorem because the trigonometric functions are all defined by the sides of a right triangle.

a^2 + b^2 = c^2

a = the adjacent side = 3

b = the opposite side = b

c = the hypotenuse = 5

3^2 + b^2 = 5^2

9 + b^2 = 25

b^2 = 16

b = 4

User Cyague
by
7.7k points

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