Answer:
E = 25 J
Step-by-step explanation:
Given that,
Spring constant, k = 200
Compression, x = 0.5
We need to find the potential energy stored in the spring. The formula for the stored potential energy in the spring is given by :
![E=(1)/(2)kx^2](https://img.qammunity.org/2022/formulas/physics/college/zsnf95pm5xgp1ar7290akfnetzsidp0d2a.png)
Put all the values,
![E=(1)/(2)* 200* 0.5^2\\\\E=25\ J](https://img.qammunity.org/2022/formulas/physics/high-school/rzj7h0ywgdmo0tsvb9lma3svstd0wvc4u3.png)
So, 25 J of potential enersy is stored in the spring.