Question

an arrow is shot vertically upward from a platform 33ft high at a rate of 174 ft/sec. when will the arrow hit the ground?​

Answer 1

h(t) = -16t2 + 186t + 43

at the ground h = 0

hence; -16t2 + 186t + 43 = 0

solving this quadratic equation using the quadratic formula ; a = -16, b = 186, c = 43 ; x = (-b +-(b2 - 4ac)1/2)/2a

gives t = 11.8 seconds to the nearest tenth (note that the negative root has no practical significance)

Explanation: