Answer:
the maximum area enclosed = 1125000sq. ft.
Explanation:
Let each side perpendicular to the river be "x".
Then the side parallel to the river is "3000-2x".
Now, area of the rectangle
A(x) = (3000-2x)x
A(x) = -2x^2+3000x
Which is a quadratic equation with a = -2 and b = 3000
Maximum area occurs where x = -b/2a
x = -3000/(-2×2) = 750 ft.
Therefore, width of rectangle x = 750 ft
Now, length = 3000-2(750) = 1500 ft.
Therefore, the maximum area enclosed = 1500×750 = 1125000 sq. ft.