Question

An average 1.50 V Alkaline AA battery has 9,360 J of stored energy. If the battery is placed in a toy that requires 2.00 amperes of current to operate, how many minutes will the battery last before it runs out of energy?​

Answer 1

52 minutes

Step-by-step explanation:

Given the following data;

Voltage = 1.5 V

Current = 2 Amperes

Energy = 9360 J

To find how many minutes will the battery last before it runs out of energy;

First of all, we would determine the power rating of the toy

Power = current * time

Power = 2 * 1.5

Power = 3 Watts

Next, we find the time;

Energy = power * time

9360 = 3 * time

Time = 9360/3

Time = 3120 seconds

To convert to minutes;

60 seconds = 1 minute

3120 seconds = 3120/60 = 52 minutes