Question

A gas at constant volume has a pressure of 2.80 atm at 400. K. What will be the pressure of the gas at 360. K? (4 points)

2.52 atm
2.94 atm
3.11 atm
3.78 atm

Answer 1

It's 2.52

Step-by-step explanation:

This requires Gay-Lussac's Law, in which the relationship is P1 / T1 = P2 / T2. "P" stands for Pressure and "T" is Temperature. The first pressure is 2.80, the first temperature is 400 Kelvin, the second pressure is unknown (that's what your solving for), and your second temperature is 360 Kelvin. Because you don't have the second pressure, your equation will look like 2.80 atm x 360 K / 400. This will tell you that the pressure of the gas at 360 K will be 2.52.

I also took the test and it was correct.

Answer 2

Option first 2.52 atm

Answer:

Solution given:

pressure 1[P1]=2.8atm

pressure 2[P2]=?

temperature [T1]=400k

temperature [T2]=360k

now

By using gas equation

P1V1/T1=P2V2/T2

since

volume is constant

P1/T1=P2/T2

2.8/400=P2/360

P2=2.8*360/400

P2= 2.52