Question

Leo is visiting New York City to see the Empire State building. He knows that the Empire State building is 1,484 feet tall. When he spots it, he stops and has to look up at an angle of 84.7 degrees to see the top. How far away from the base of the Empire State building is he?[plz help mee!!]​

Answer 1

a = 137.6

Explanation:

The building and the street make a 90 degree angle. You have the length b, which is the height 1,484ft. The angle B 84.7 is created where he stands and looks up.

First, find the missing hypotenuse, c. Your angel A is 180 - 90 -84.7 = 5.3

The sine of an angle is equal to the ratio of the opposite side to the hypotenuse.

sin( B)=opp/hyp

sin(84.7) = 1484 / c

c = 1484/sin(84.7)

c=1490.37

Find the last side of the triangle, in this case the distant from Leo to the building, using the Pythagorean theorem.

`a^(2) +b^(2) =c^(2) \\a^(2) = c^(2) -b^(2) \\a^(2) =1490.37^(2) -1484^(2) \\a=137.6`