Question

You are the owner of a local fast food restaurant and you want to test whether your average number of customers per day is less than 500. You take a sample of 25 days and find that the average for these days is 480. You have been told by the corporate office that the population standard deviation of the number of customers is 95. What is the p-value for a hypothesis test at a 5% significance level

Answer 1

The correct answer is "-1.05".

Explanation:

Given that,

Sample size,

n = 25

Sample mean,

`\bar X=480`

Population standard deviation,

`\sigma=95`

Null hypothesis,

`H_0:\mu=500`

Alternate hypothesis,

`H_0:\mu>500`

Then,

The p-value will be:

⇒
`Z=(\bar X-\mu)/((\sigma)/(√(n) ) )`

By putting the values, we get

⇒
`=(480-500)/((95)/(√(25) ) )`

⇒
`=-(100)/(95)`

⇒
`=-1.05`