Question

HELP PLEASE !!!!!!!!!!!

Answer 1

option B

Explanation:

`\lim_(x\to \infty) f(x) = \lim_(x \to \infty) (log(x+2)-3 )`

`= \lim_(x \to \infty) ( log(x+2)) - \lim_(x \to \infty) 3\\\\=\infty - 3\\\\= \infty`

`\lim_(x \to 2) f(x) = \lim_(x \to 2) ( log(x+2)) - \lim_(x \to2) 3\\\\`

`= log( 2 + 2 ) - 3\\\\= log 4 - 3\\\\=log(2^2) -3\\\\=2 log 2 -3`

`\lim_(x \to -2) f(x) = \lim_(x \to -2) ( log(x+2)) - \lim_(x \to -2) 3\\\\`
`\lim_(x \to -2)_+ f(x) = \lim_(x \to -2_+) ( log(x+2)) - \lim_(x \to -2_+) 3 = -\infty\\\\\lim_(x \to -2_-) f(x) = \lim_(x \to -2)_- ( log(x+2)) - \lim_(x \to -2)_- 3 = -\infty\\\\\\\lim_(x \to -2) f(x) = - \infty`