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A spring, with a spring constant of 4000 N/m, is oriented horizontally, and compressed by 10cm. When released, the spring launches a block of mass 1.0 kg along a 5.0-m horizontal section of track, where the coefficient of friction between the block and track is 0.20. The block then goes up a frictionless ramp angled at 60o with the horizontal. How high up the ramp does the block go before it starts to slide back down

User Areza
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1 Answer

4 votes

Answer:


d=1.2m

Step-by-step explanation:

From the question we are told that:

Spring constant
k= 4000 N/m

Compressed
l_d= 10cm=>0.10

Mass
m=1.0kg

Length of horizontal section
l=5.0-m

Coefficient of friction
\mu=0.20

Angle
\theta=60 \textdegree

Generally the equation for Kinetic Energy K.E is mathematically given by


K.E=\mu mgL+mgdsin\theta


(1)/(2)k*l_d^2=\mu mgL+mgdsin\theta


(1)/(2)(4000)*0.1^2=0.2*1*9.8*5+1*9.8*d*sin60


d=1.2m

User Rvanlaarhoven
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