Answer:
a+k ≤ 35
8a+4k ≤ 190
Some possible combinations are 10 adults and 20 kids
5 adults and 29 kids
Explanation:
Let k= number of kids
a = number of adults
a+k ≤ 35 since you can have at most 35
8a + 4k ≤ 190 since the most you can spend is 190
Some possible combinations are 10 adults and 20 kids
(10+30 < 35 and 8*10+4*20 = 80+80 =160< 190)
Another possible combination
5 adults and 29 kids
(5+29 < 35 and 5*10 + 4*29 =50+116=166)