Question

Calculate the total energy, in kilojoules, that is needed to turn a 46 g block

of ice at -25 degrees C into water vapor at 100 degrees C.

Answer 1

Answer: The total energy, in kilojoules, that is needed to turn a 46 g block of ice at -25 degrees C into water vapor at 100 degrees C is 11.787 kJ.

Step-by-step explanation:

Given: Mass = 46 g

Initial temperature =
`-25^(o)C`

Final temperature =
`100^(o)C`

Specific heat capacity of ice = 2.05
`J/g^(o)C`

Formula used to calculate the energy is as follows.

`q = m * C * (T_(2) - T_(1))`

where,

q = heat energy

m = mass

C = specific heat capacity

`T_(1)` = initial temperature

`T_(2)` = final temperature

Substitute the values into above formula as follows.

`q = m * C * (T_(2) - T_(1))\\= 46 g * 2.05 J/g^(o)C * (100 - (-25))^(o)C\\= 11787.5 J (1 J = 0.001 kJ)\\= 11.787 kJ`

Thus, we can conclude that the total energy, in kilojoules, that is needed to turn a 46 g block of ice at -25 degrees C into water vapor at 100 degrees C is 11.787 kJ.