Question

A man leaves the town of Elmsville at 8:00 am and drives to Oak City at a constant rate of 50 miles per hour. Two hours later, a woman leaves Elmsville following the same route to Oak City. The man and woman arrive in Oak City at 3:00 p.m. What was the rate of the woman

Answer 1

Answer: 70 mph

Explanation:

Given

A man leaves the town of Elmsville at 8:00 am and reach oak city at 3 Pm

Rate of driving is 50 miles per hour

time taken by man
`t=7\ hr`

Woman leaves 2 hour later and reach by 3 Pm, so time taken is
`5\ hr`

Distance traveled by both the person is same

`\therefore 50* 7=v* 5\quad[v=\text{rate of woman}]\\\\\Rightarrow v=(50* 7)/(5)\\\\\Rightarrow v=70\ mph`

Thus , the rate of woman is 70 miles per hour.