Question

PLEASE HELP

IM BEGGING PLEASE

Lake Pyramid, Nevada is one of the best places in the connected 48 states to
catch trophy cutthroat trout. History shows that about 37% of guest catch a
cutthroat. Let X be a random variable that represents the first trip to Lake
Pyramid on which a guest catches a cutthroat. Let X be a random variable that
represents the first trip to Lake Pyramid on which a guest catches a cutthroat.
Find the probability that it takes the fisher no more than 4 trips to catch a
cutthroat. . *

Answer 1

If an event occurs 0 times (out of 4, in this case) then it does not occur at least once. So we can find the probability of it not occurring and then subtract that value from 1.

So, what are the chances of it not occurring in 1 trip?

1−.37=.63

What about not occurring in 2 trips?

(1−.37)⋅(1−.37)=.63⋅.63=.3969

Now what about not occurring in 4 trips?

.63^4 = 0.15752961

We must subtract this value from 1

(recall that what we just calculated is the probability of it not occurring, so the probability of it occurring at least once is:

1−0.15752961 = .84247039

TLDR - In 4 trips the chance of a guest catching a cutthroat once in under 4 trips in 0.84.