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Which is the product of (1 +41+3x) (2 - 7x–9x)?​

User Bdwey
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1 Answer

3 votes

Answer:

-48x^2 -666x+84

Explanation:

Exponet is ^2.

Multiply is •

Use Distributed Property. Multiply the second parathesis by each term from the first parathesis.

Any expression multiplied by 1 remains the same. Distribute 41 through the parathesis. 41(2-7x-9x).

Distribute 3x through the parathesis 3x • (2-7x-9x).

You will have these numbers left: (Slide 2)

Add the numbers, 2 and 82 to get 84. Add -7x -9x + -287x -369x + 6x to get -666x. Add -21x^2 - 27x^2 to get 48x^2.

Use the communitative property to reorder the terms. And then your answer is -48x^2 -666x+84.

Which is the product of (1 +41+3x) (2 - 7x–9x)?​-example-1
Which is the product of (1 +41+3x) (2 - 7x–9x)?​-example-2
User Thilaw Fabrice
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