Answer:
![U_x = (1)/(2) kx^2](https://img.qammunity.org/2022/formulas/physics/high-school/s366hfdu0pvhx0dkawyl9xxfatnuhfd0gg.png)
Step-by-step explanation:
Find the image uploaded for the chart.
The energy stored in a stretched elastic material is known as elastic potential energy. Mathematically this energy is expressed as follows;
![U_x = (1)/(2) fx\\\\where ;\\\\f = kx\\\\U_x = (1)/(2)kx^2](https://img.qammunity.org/2022/formulas/physics/high-school/40q7mo0wn5lx95medvhqydzh4yxqnq4alu.png)
The terms are defined as follows;
f is the load applied to the elastic material (N)
k is the spring constant (N/m)
x is the extension of the material (m)
Ux is the elastic potential energy (J)