Question

The rotating loop in an AC generator is a square 18 cm on each side. It is rotated at 60.0 Hz in a uniform magnetic field of 0.3T. Calculate the approximate value of the maximum amplitude of the power delivered to the loop for a loop resistance of 12 ohm ?

Answer 1

The maximum amplitude power is 1.12 W

Step-by-step explanation:

Given;

length of each side of the square, L = 18 cm = 0.18 m

angular frequency, f = 60 Hz

magnetic field, B = 0.3 T

resistance of the loop, R = 12 ohm

The area of the loop, A = L² = 0.18 m x 0.18 m = 0.0324 m²

The angular speed, ω = 2πf = 2π x 60 = rad/s = 377.04 rad/s

The maximum value of emf induced;

`E_(max) = NBA \omega\\\\where; \\N \ is \ number \ of \ turns\\\\E_(max) = (1) * 0.3 * 0.0324 * 377.04\\\\E_(max) = 3.665 \ V`

The maximum amplitude power is calculated as;

`Power = ((E_(max))^2 )/(R) \\\\Power = ((3.665)^2)/(12) \\\\Power = 1.12 \ W`