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How much power does it take to lift 70.0 N to 5.0 m high in 5.00 s?

User Vck
by
7.3k points

1 Answer

4 votes

Answer:

Power = 70 W

Step-by-step explanation:

Given that,

Force, F = 70 N

Height, h = 5 m

Time, t = 5 s

We need to find the power of the object. We know that,

Power = work done/time

Put all the values,


P=(Fd)/(t)\\\\P=(70* 5)/(5)\\\\P=70\ W

So, the required power is 70 W.

User Ultranaut
by
7.9k points

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