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238 U 92 write the following decay sequence.​

238 U 92 write the following decay sequence.​-example-1

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Answer: The given decay sequence is
^(238)_(92)U \rightarrow ^(234)_(90)Th + ^(4)_(2)He \rightarrow ^(234)_(91)Pa + ^(0)_(-1)\beta.

Step-by-step explanation:

An alpha-particle is a helium atom. Hence, when an alpha decay occurs in
^(238)_(92)U then the reaction equation is as follows.


^(238)_(92)U \rightarrow ^(234)_(90)Th + ^(4)_(2)He

Now, in sequence the equation for beta decay is as follows.


^(234)_(90)Th \rightarrow ^(234)_(91)Pa + ^(0)_(-1)\beta

Hence, the sequence will be as follows.


^(238)_(92)U \rightarrow ^(234)_(90)Th + ^(4)_(2)He \rightarrow ^(234)_(91)Pa + ^(0)_(-1)\beta

Thus, we can conclude that the given decay sequence is
^(238)_(92)U \rightarrow ^(234)_(90)Th + ^(4)_(2)He \rightarrow ^(234)_(91)Pa + ^(0)_(-1)\beta.

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