Given:
The equation is:
![270=3e^(2.4K)](https://img.qammunity.org/2022/formulas/mathematics/high-school/8l8rcmbzbbi4if4krtd4ctk3lsbv647cuy.png)
To find:
The solution for the given equation to the nearest hundredth.
Solution:
We have,
![270=3e^(2.4K)](https://img.qammunity.org/2022/formulas/mathematics/high-school/8l8rcmbzbbi4if4krtd4ctk3lsbv647cuy.png)
Divide both sides by 3.
![(270)/(3)=e^(2.4K)](https://img.qammunity.org/2022/formulas/mathematics/high-school/ys0nah27jfrd08vjjr5fva1j3gxrs1qpuh.png)
![90=e^(2.4K)](https://img.qammunity.org/2022/formulas/mathematics/high-school/up72g2z4p5zngu7l3twtsk1h6vbjfuxdta.png)
Taking ln on both sides, we get
![\ln (90)=\ln e^(2.4K)](https://img.qammunity.org/2022/formulas/mathematics/high-school/t4xe226bxeaatq7a1i1sf024s4qv4984wy.png)
![[\because \ln e^x=x]](https://img.qammunity.org/2022/formulas/mathematics/high-school/m24tge2dslw94bp9jx3y240611r7x9yr3r.png)
Divide both sides by 2.4.
![(\ln (90))/(2.4)=K](https://img.qammunity.org/2022/formulas/mathematics/high-school/2q6yoh00exv4akwivij30u0jx0j618o92e.png)
![[\because \ln (90)\approx 4.4998]](https://img.qammunity.org/2022/formulas/mathematics/high-school/mst1teg1g36yldlzr527t40fds1x7m0r6w.png)
![1.874916667=K](https://img.qammunity.org/2022/formulas/mathematics/high-school/r0nf6oik7u10o0f7zmrtdvtwgp9kqd3rod.png)
Round the value to the nearest hundredth (two decimal place)
![K\approx 1.87](https://img.qammunity.org/2022/formulas/mathematics/high-school/ai6c30st1aw0aoycuxoujn0h959elo0175.png)
Therefore, the value of K is 1.87.