Question

What is the molarity if 60.4 grams of hydrochloric acid was added to 505 mL of water?

M
H - 1.0079 g/mol
Cl- 35.453 g/mol

Answer 1

3.29 M

Step-by-step explanation:

Molarity refers to the molar concentration of a solution and it can be calculated using the formula below:

Molarity (M) = number of moles (n) ÷ volume (V)

According to this question, the mass of HCl was given to be 60.4 grams and the volume of water as 505 mL.

Using mole = mass/molar mass to convert mass of HCl to moles

Molar mass of HCl = 1.0079 + 35.453 = 36.4609g/mol

mole = 60.4g ÷ 36.4609g/mol

mole = 1.66mol

Volume of water = 505mL = 505/1000 = 0.505L

Molarity, M = 1.66 ÷ 0.505

Molarity of HCl solution = 3.29 M