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The function P(t) = 4000(1.2) represents

the population of a small island
a. Does the function represent exponential
growth or decay?
b. what is the yearly percentage change in
population?
c. estimate how many people will be living on the island after 5 years.

User Alecwhardy
by
5.3k points

1 Answer

2 votes

Given:

Consider the given function is:


P(t)=4000(1.2)^t

To find:

a. The type of exponential function (growth or decay).

b. Percentage change in population.

c. Population after 5 years.

Solution:

a. The general exponential function is:


P(t)=P_0(1+r)^t ...(i)

Where,
P_0 is the initial population and r is the rate of change in decimal.

If r<0, then the function represents exponential decay and if r>0, then the function represents exponential growth.

We have,


P(t)=4000(1.2)^t

It can be written as:


P(t)=4000(1+0.2)^t ...(ii)

On comparing (i) and (ii), we get


P_0=4000


r=0.2

Since r>0, therefore the given function represents exponential growth.

b. From part (a), we have


r=0.2

So, the rate of change in the population is 0.2. Multiply is by 100 to get the percentage change in population.


r\%=0.2* 100


r\%=20\%

Therefore, the yearly percentage change in population is 20%.

c. We have,


P(t)=4000(1.2)^t

Substitute
t=5 in the given function to find the population living on the island after 5 years.


P(5)=4000(1.2)^5


P(5)=4000(2.48832)


P(5)=9953.28


P(5)\approx 9953

Therefore, the estimated population living on the island after 5 years is 9953.

User Bhurlow
by
5.6k points