Answer:
a) 4.74 * 10^-23 cm^3
b) 8.9 g/cm^3
Step-by-step explanation:
Given data :
Lattice parameter of copper = 0.362 nM
Atomic weight of copper = 63.54 g/mole
Given that copper forms a fcc structure
a) Calculate the volume of the unit cell
V = a^3
= ( 0.362 * 10^-7 cm )^3 = 4.74 * 10^-23 cm^3
b) Calculate density of copper in g/cm^3
Density = ( n*A ) / ( Vc * NA) ----------- ( 1 )
where: NA = Avogadro's number = 6.022 * 10^23 atoms/mol
n = number of atoms per unit cell = 4
A = atomic weight = 63.54 g/mol
Vc = volume of unit cell = 4.74 * 10^-23 cm^3
Input values into equation 1
Density = 8.9 g/cm^3