Question

The fastest pitched baseball was clocked at 47 m/s. Assume that the pitcher exerted his force (assumed to be horizontal and constant) over a distance of 1.0 mm, and a baseball has a mass of 145 g.

Required:
a. Draw a free-body diagram of the ball during the pitch.
b. What force did the pitcher exert on the ball during this record-setting pitch?
c. Estimate the force in part b as a fraction of the pitcher's weight.

Answer 1

Following are the solution to the given points:

Step-by-step explanation:

For point a:

Find the schematic of the empty body and in attachment. Upon on ball during the pitch only two forces act:

The strength of the pitcher F is applied that operates horizontally. Its gravity force acting on an object is termed weight, which value is where m denotes mass, and g the acceleration of gravity.

For point b:

`160.2\ N`

First, they must find that ball's acceleration. You can use the SUVAT equation to achieve that

where

`v = 47\ (m)/(s) \\\\u = 0 \\\\a =?\\\\d = 1.0 \ m \\\\`

Solving for a,

`a=(v^2-u^2)/(2d)=(47^2-0)/(2(1.0))=1104.5 \ (m)/(s^2)`

Calculating the mass:

`m = 145 g = 0.145 kg`

Calculating the force:

`F=ma=0.145 * 1104.5= 160.2 \ N`

For point c:

0.195 times the pitcher's weight

`m = 84 \ kg \\\\g = 9.8\ (m)/(s^2)\\\\`

Solving for W:

`W=84 * 9.8= 823.2 \ N`

Now the force of Part B could be defined as the fraction of the mass of the pitcher:

`(F)/(W)=(160.2)/(823.3)=0.195`