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Find the 59th term of the arithmetic sequence
29,37,45,...

User Arka
by
8.3k points

1 Answer

4 votes

Answer:

13,456

Explanation:

Tn= a+(n-1)d

a is the first term, n is the given number and d is the common difference. d is given by subtracting the first term from the second term or the second from the third. Therefore the the 59th term of the sequence 29, 37, 45 is,

Tn= 29+(59-1)8

=29(58)8

=13,456

User Turk
by
7.8k points

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