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ABCD is a parallelogram in which cd = 7cm Ad = 5cm ND adc = 125.. Find correct to one decimal place the area of the parallelogram.

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Answer:

28.7cm²

Explanation:

The sketch of the parallelogram is attached to this response.

As shown in the sketch,

h is the height of the parallelogram

ADC is 125°

AD = 5cm

CD = 7cm

Also

Since the adjacent angles of a parallelogram are supplementary (add up to 180°), it means that;

=> ADC + BCD = 180°

=> 125° + BCD = 180°

=> BCD = 180° - 125°

=> BCD = 55°

The area (A) of a parallelogram is given by;

A = b x h ----------(i)

Where

b = base of the parallelogram

h = height of the parallelogram

From the sketch,

b = CD = 7cm

h can be found by using the sine trigonometric function as follows

sin BCD =
(h)/(BC)

=> sin 55° =
(h)/(5)

=> h = 5 sin 55°

=> h = 5 x 0.8192

=> h = 4.096cm

Now, substitute the values of h and b into equation (i) as follows;

A = 7 x 4.096

A = 28.672

A ≅ 28.7 (to one decimal place)

Therefore, the area of the parallelogram is 28.7cm²

ABCD is a parallelogram in which cd = 7cm Ad = 5cm ND adc = 125.. Find correct to-example-1
User Victor K
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