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Let ​f(x)=x^2+6x−16​.
Enter the x-intercepts of the quadratic function in the boxes.

Let ​f(x)=x^2+6x−16​. Enter the x-intercepts of the quadratic function in the boxes-example-1

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\underline{\underline{\large\bf{Given:-}}}


\red{\leadsto}\:
\textsf{}
\sf f(x)= x^2+6x−16


\underline{\underline{\large\bf{To Find:-}}}


\orange{\leadsto}\:
\textsf{ x-intercepts of the quadratic function }
\sf


\\


\underline{\underline{\large\bf{Solution:-}}}\\


\longrightarrowx- intercept is the point where graph of given function touches the x-axis,f(x) becomes 0 at the point where graph of given function touches the x-axis. Therefore, we would to solve x^2+6x−16=0 and find its root.


\begin{gathered}\\\implies\quad \sf x^2+6x−16=0 \\\end{gathered}


\begin{gathered}\\\implies\quad \sf x^2+8x-2x −16=0 \\\end{gathered}


\begin{gathered}\\\implies\quad \sf x(x+8)-2(x+8)=0 \\\end{gathered}


\begin{gathered}\\\implies\quad \sf (x-2)(x+8)=0\\\end{gathered}


\begin{gathered}\\\implies\quad \sf x=2\quad or \quad x=-8 \\\end{gathered}


\leadstox-intercepts of the given quadratic function are 2 and -8 .

User BJ Anderson
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