Question

A researcher is investigating whether a difference exists in the mean weight of green-striped watermelons grown on two different farms: one that uses organic methods and one that uses nonorganic methods. The mean and standard deviation of the weights in a random sample of 43 watermelons from the organic farm were 18 pounds and 2 pounds, respectively. The mean and standard deviation of the weights in a random sample of 40 watermelons from the nonorganic farm were 20 pounds and 1.7 pounds, respectively.

Required:
What represents the standard error of the difference in the mean weights of watermelons from the two farms?

Answer 1

D. 2^2+1.7^243+40−−−−−√

Explanation:

The computation is shown below:

Given that

Sample 1

n_1 = 43

mean = 18

s_1 = 2

Sample 2

n_2 = 40

mean = 20

s_2 = 1.7

Now the standard error is

`= \sqrt{(s_1^2)/(n_1) + (s_2^2)/(n_2) } \\\\= \sqrt{(2^2)/(43) + (1.7^2)/(40) }`

= 0.4065