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Answer:
let total be U and strawberry be S and.apple be A .
now
n[U]=200
n[S]=56% 0f 200=112
n[A]=44%of 200=88
n[A n S]=30%of 200=60
we have
n[U]=n[A] +n[B]-n[ A n B]+
=200-112-88+60=60
option C. 60 is a required answer.
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