Question

For each sequence, find the first 4 terms and the 10th term.
a) 12-n
B 5 - 2n

Answer 1

Solution given:

a.

tn=12-n

1 st term =12-1=11

2nd term =12-2=10

3rd term=12-3=9

4th term=12-4=8

10th term=12-10=2

b.

tn=5-2n

1st term=5-2*1=3

2nd term=5-2*2=1

3rd term=5-2*3=-1

4th term=5-2*4=-3

10th term=5-2*10=-15

Answer 2

(a) Solution

T(n) = 12 - n

T(1) = 12 - 1 = 11

T(2) = 12 - 2 = 10

T(3) = 12 - 3 = 9

T(4) = 12 - 4 = 8

T(10) = 12 - 10 = 2

(b) Solution

T(n) = 5 - 2n

T(1) = 5 - 2 = 3

T(2) = 5 - 4 = 1

T(3) = 5 - 6 = -1

T(4) = 5 - 8 = -3

T(10) = 5 - 20 = -15