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A body is dropped from a height H. In how much time will it reach the ground?

User Vlumi
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1 Answer

1 vote

Answer:


s = ut + (1)/(2) g {t}^(2) \\ t(u + (1)/(2) gt) = H \\ u + (1)/(2) gt = H \\ t = 2(H - u) / g \\ t = ((H - u))/(5) \\ u \: is \: speed \: or \: velocity

User Chyoo CHENG
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