Question

In right triangle ABC, sin M = cos 61. If 0

Answer 1

Note: Consider we need to find the value of M if
`0^\circ<M<90^\circ`

Given:

In a right triangle ABC,

`\sin M=\cos 61^\circ`

To find:

The value of M.

Solution:

We have,

`\sin M=\cos 61^\circ`

It can be rewritten as:

`\sin M=\cos (90^\circ-29)^\circ`

`\sin M=\sin 29^\circ`
`[\because \sin (90^\circ-\theta)=\sin \theta]`

On comparing both sides, we get

`M=29^\circ`

Therefore, the value of M is 29 degrees.