209k views
4 votes
A bell rings at a frequency of 75hz on a warm 25 degree evening. calculate the...

a. speed of the sound wave at this temperature.
b. wavelength of the sound wave

1 Answer

1 vote

Answer:

Step-by-step explanation:

We need 2 different equations for this problem: first the velocity of sound equation, then the frequency of the sound equation.

The velocity of sound is found in:

v = 331.5 + .606T

We need to find that first in order to fill it into the frequency equation which is


f=(v)/(\lambda) where v is the velocity we will find the part a, f is frequency and lambda is the wavelength. Starting with the velocity of the sound:

v = 331.5 + .606(25) and

v = 331.5 + 15 and rounding correctly using the rules for sig fig when adding:

v = 347 m/s

Filling that into the frequency equation:


75=(347)/(\lambda) and


\lambda=(347)/(75) so


\lambda=4.6m

User Aitwar
by
4.6k points