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Write an equation of the line that passes through the points (3.2) and (6,11). Show your work!

User Janco
by
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1 Answer

5 votes

Answer:


y=3x-7

Explanation:

Hi there!

Linear equations are typically organized in slope-intercept form:
y=mx+b where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis)

1) Determine the slope (m)


m=(y_2-y_1)/(x_2-x_1) where the points given are
(x_1,y_1) and
(x_2,y_2)

Points (3,2) and (6,11)


=(11-2)/(6-3)\\=(9)/(3)\\= 3

Therefore, the slope of the line is 3. Plug this into
y=mx+b:


y=3x+b

2) Determine the y-intercept (b)


y=3x+b

Plug in one of the given points and solve for b


2=3(3)+b\\2=9+b

Subtract 9 from both sides


2-9=9+b-9\\-7=b

Therefore, the y-intercept of the line is -7. Plug this back into
y=3x+b:


y=3x-7

I hope this helps!

User Fakataha
by
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