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(6 - i)(6 + i) multiplying complex numbers​

1 Answer

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Answer:


(6 - i)(6 + i) \\ = (36 + 6i - 6i - {i}^(2) ) \\ = 36 - {i}^(2) \\ = 36 - ( - 1) \\ = 36 + 1 \\ = 37

User Anshul Nigam
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