121k views
3 votes
Please helpppp... thank u ❤️​

Please helpppp... thank u ❤️​-example-1
User Jcromanu
by
4.7k points

2 Answers

3 votes

Answer:

the highest point for the first question is 0 meters per second

the answer for question 2 is 45 degrees

User Eugene Komisarenko
by
5.2k points
7 votes

Answer:

For Ryan:


at \: highest \: point : v = 0 \\ velocity = 0 \: {ms}^( - 1)

For the football kicked:


s = ut - (1)/(2) g {t}^(2) \\ for \: range : s = 0 \\ u \sin( \theta) = (gt)/(2) \\ t = (2u \sin(\theta) )/(g) \\ range(x) = ut \\ x = \frac{ {2u {}^(2) \sin(\theta) }^{} }{g} \\ \frac{50 * 9.8}{ {2318.9}^{} } = \sin(\theta) \\ \\but \: 0 = u \sin(25) - 2 * 9.8 * 50 \\ u = 2318.9 \: {ms}^( - 1) \\ \theta = 12.2 \degree

User JiminP
by
4.7k points