Question

79. If the takeoff velocity of an airplane on a runway is 300 km/hr with an acceleration of 2 m/s. What is the takeoff time

of the airplane.

Answer 1

The take off time is equal to 41.66s.

Step-by-step explanation:

Given that,

The initial speed of the airplane, u = 0

Acceleration, a = 2 m/s²

Let v is the take off time. Using first equation of motion,

v = u +at

Put v = 300 km/hr = 83.3 m/s

So,

`t=(v)/(a)\\\\t=(83.33)/(2)\\\\t=41.66\ s`

So, the take off time is equal to 41.66s.